Bead Craft Project

Call mathematical experts ... please help?

1.Sarah has saved $ 54. On Wednesday, he spent three dollars of their savings. What percentage represents the portion of your total savings still left? AB 17:18 15:16 1:09 8:09 2 DC. That pair of ratios form a proportion? A.4/14 and June 27 / 10/21 B.8/16 and C.6 / 9 and 9 / 12 and 10/25 D.6/15 3.Compare -17 / 5 -15.9 __. A. <B.> C.equal 4. Solve the equation 20 = h/-10. h = ____. 5.Simplify -9 (-8). 6.A bag of pearls for a project to ship weighs 6 oz The project uses five bags. The total weight of the accounts in pounds as a decimal is 1875 pounds. true or false 7.Evaluate (4p - M) ÷ 4 for m = -4 and p = 2 8.Which ordered pair is a solution of the equation y = 2.5x + 6.5? A. (4, -1) B. (4, -2) C (-1, 4) D. (-2, 4) very appreciated

1. A. From $ 54, which has 51 left, so the ratio is 51/54. Numberator Divide the denominator by 3, so the answer A. 2. D. Divide the numerator and the denominator of 6.15 by 3 to obtain the proportion of 2 / 5 10/25 numbers and divide by 5 to get 2 / 5, so the same amount. 3. B. -17 / 5 is equal to -3.4 and that number is greater than -15.9, but if one of the symbols are not correct and the number is assumed to be -17.5 or other number was -15 / 9, then the answer be A. 4. H = -200. Multiply both sides of the equation by -10 to get rid of the denominator in H, so that h = 20 *- 10, which will give the answer -200. 5. 72-9 * 8 * 72 and a negative = positive negative 6. 5 bags = 30 oz of accounts. There are 16 ounces in a pound to 30 / 16 = 1.875, so the answer is true. 7. The answer is 3 (4 * 2 to -4) / 4. First do the multiplication inside the parentheses and brackets are done first to arrive (8-4) / 4, now is a bad thing remains the same to add, and you get 12 / 4, which is 3. 8. C. Substituting each value instead of X and Y in the equation and do the math in A, if x = 4 and should be 16.5, the same is true for answer B, D, if x = -2, then Y would be 1.5. Only C is the right combination. Answers with explanations, in case.

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